Two boys are standing at the ends 𝐴 and 𝐵 of a ground where 𝐴𝐵 = 𝑎. The boy at 𝐵 starts running in a direction perpendicular to 𝐴𝐵 with velocity 𝑣1. The boy at 𝐴 starts running simultaneously with velocity 𝑣 and catches the other boy in a time 𝑡, when 𝑡 is

April 10, 2022

by Ezee_Notes

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Physics Problems

Question : Two boys are standing at the ends 𝐴 and 𝐵 of a ground where 𝐴𝐵 = 𝑎. The boy at 𝐵 starts running in a direction perpendicular to 𝐴𝐵 with velocity 𝑣1. The boy at 𝐴 starts running simultaneously with velocity 𝑣 and catches the other boy in a time 𝑡, when 𝑡 is

(A) $\dfrac{a}{\sqrt{\left[ v^{2}+V_{1}^{2}\right] }}$

(B) $\sqrt{a^{2}/\left( V^{2}-V_{1}^{2}\right) }$

(D) $a/\left( v-v_{1}\right)$

Answer : option (B)

Solution :

Two boys are standing at the ends 𝐴 and 𝐵 of a ground where 𝐴𝐵 = 𝑎. The boy at 𝐵 starts running in a direction perpendicular to 𝐴𝐵 with velocity 𝑣1. The boy at 𝐴 starts running simultaneously with velocity 𝑣 and catches the other boy in a time 𝑡, when 𝑡 is