Two bodies are thrown simultaneously from a tower with same initial velocity 𝑣0: one vertically upwards, the other vertically downwards. The distance between the two bodies after time 𝑡 is

Question : Two bodies are thrown simultaneously from a tower with same initial velocity 𝑣0: one vertically upwards, the other vertically downwards. The distance between the two bodies after time 𝑡 is

(A) 2v_{0}t+\dfrac{1}{2}gt^{2}

(B) 2v_{0}t

(C) v_{0}t+\dfrac{1}{2}gt^{2}

(D) v_{0}t

Answer : option (B)

Solution :

Two bodies are thrown simultaneously from a tower with same initial velocity 𝑣0: one vertically upwards, the other vertically downwards. The distance between the two bodies after time 𝑡 is
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