Question : Two bodies are thrown simultaneously from a tower with same initial velocity 𝑣0: one vertically upwards, the other vertically downwards. The distance between the two bodies after time 𝑡 is
(A) 2v_{0}t+\dfrac{1}{2}gt^{2}
(B) 2v_{0}t
(C) v_{0}t+\dfrac{1}{2}gt^{2}
(D) v_{0}t
Answer : option (B)
Solution :
