Question : Two balls 𝐴 and 𝐵 are thrown simultaneously from the top of a tower. 𝐴 is thrown vertically up with a speed of 4ms −1 . 𝐵 is thrown vertically down with a speed of 4 ms −1 . The ball 𝐴 and 𝐵 hit the ground with speed 𝑣𝐴 and 𝑣𝐵 respectively. Then
(A) v_{A} <v_{B}
(B) v_{A} >v_{B}
(C) v_{A}\geqq v_{B}
(D) v_{A}=v_{B}
Answer : option (D)
Solution :
