# The time taken by the projectile to reach from 𝐴 to 𝐵 is 𝑡, then the distance 𝐴𝐵 is equal to

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(A) 2 𝑢 t

(B) $\sqrt{3}$ 𝑢t

(C) $\dfrac{\sqrt{3}}{2}ut$

(D) $\dfrac{ut}{\sqrt{3}}$

Answer : option (D)

Solution :

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