**Question **: The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is

(A) 1-\left( \dfrac{4}{5}\right) ^{10}

(B) \left( \dfrac{1}{5}\right) ^{10}

(C) 1-\left( \dfrac{1}{5}\right) ^{10}

(D) \left( \dfrac{4}{5}\right) ^{10}

**Answer**: option (A)

**Solution **:

The probability of hitting a target is p=\dfrac{1}{5}.

Therefore, the probability of not hitting a target is q=1-\dfrac{1}{5}=\dfrac{4}{5}.

Hence, the required probability is 1-\left( \dfrac{4}{5}\right) ^{10}

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