# The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is

Question : The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is

(A) $1-\left( \dfrac{4}{5}\right) ^{10}$

(B) $\left( \dfrac{1}{5}\right) ^{10}$

(C) $1-\left( \dfrac{1}{5}\right) ^{10}$

(D) $\left( \dfrac{4}{5}\right) ^{10}$

Answer: option (A)

Solution :

The probability of hitting a target is $p=\dfrac{1}{5}$.
Therefore, the probability of not hitting a target is $q=1-\dfrac{1}{5}=\dfrac{4}{5}$.
Hence, the required probability is $1-\left( \dfrac{4}{5}\right) ^{10}$

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