Question : The probability that a marksman will hit a target is given as 1/5. Then the probability that at least once hit in 10 shots is
(A) 1-\left( \dfrac{4}{5}\right) ^{10}
(B) \left( \dfrac{1}{5}\right) ^{10}
(C) 1-\left( \dfrac{1}{5}\right) ^{10}
(D) \left( \dfrac{4}{5}\right) ^{10}
Answer: option (A)
Solution :
The probability of hitting a target is p=\dfrac{1}{5}.
Therefore, the probability of not hitting a target is q=1-\dfrac{1}{5}=\dfrac{4}{5}.
Hence, the required probability is 1-\left( \dfrac{4}{5}\right) ^{10}