The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is

The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is

Question: The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is