The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is

May 10, 2022

by Ezee_Notes

with no comment

Physics Problems

Question: The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is

(A) $\dfrac{3}{\sqrt{2}}$

(B) $\sqrt{2}$

(D) 2

Answer: Option (A)

Solution:

The potential energy of a 1 kg particle free to move along the x-axis is given by 𝑉(𝑥) = (𝑥 4/4 − 𝑥 2 2 ) J. The total mechanical energy of particle is 2 J. Then, the maximum speed (in ms−1 ) is