# The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to

Question : The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to

(A) $\tan ^{-2}\left( 2\right)$

(B) $\dfrac{\pi }{6}$

(C) $\dfrac{\pi }{6}$

(D) $\tan ^{-1}\left( \dfrac{1}{2}\right)$