The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to

Question : The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to

(A) \tan ^{-2}\left( 2\right)

(B) \dfrac{\pi }{6}

(C) \dfrac{\pi }{6}

(D) \tan ^{-1}\left( \dfrac{1}{2}\right)

Answer : option (D)

Solution :

The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to
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