Question : The maximum height attained by a projectile when thrown at an angle θ with the horizontal is found to be half the horizontal range. Then θ is equal to
(A) \tan ^{-2}\left( 2\right)
(B) \dfrac{\pi }{6}
(C) \dfrac{\pi }{6}
(D) \tan ^{-1}\left( \dfrac{1}{2}\right)
Answer : option (D)
Solution :
