The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

Question : The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

(A) \theta =\tan ^{-1}\left( \dfrac{1}{4}\right)

(B) \theta =\tan ^{-1}\left( 4\right)

(C) \theta =\tan ^{-1}\left( 4\right)

(D) 𝜃 = 45°

Answer : option (B)

solution:

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
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