**Question :** The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

(A) \theta =\tan ^{-1}\left( \dfrac{1}{4}\right)

(B) \theta =\tan ^{-1}\left( 4\right)

(C) \theta =\tan ^{-1}\left( 4\right)

(D) 𝜃 = 45°

**Answer :** option (B)

**solution:**

*Related*