Question : The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is
(A) \theta =\tan ^{-1}\left( \dfrac{1}{4}\right)
(B) \theta =\tan ^{-1}\left( 4\right)
(C) \theta =\tan ^{-1}\left( 4\right)
(D) 𝜃 = 45°
Answer : option (B)
solution:
