The block of mass 𝑀 moving on the frictionless horizontal surface collides with the spring of spring constant 𝐾 and compresses it by length 𝐿. The maximum momentum of the block after collision is

Question: The block of mass 𝑀 moving on the frictionless horizontal surface collides with the spring of spring constant 𝐾 and compresses it by length 𝐿. The maximum momentum of the block after collision is

(A) Zero

(B) \dfrac{ML^{2}}{k}

(C) \sqrt{MK}L

(D) \dfrac{KL^{2}}{2M}

Answer: Option (C)

Solution:

The block of mass 𝑀 moving on the frictionless horizontal surface collides with the spring of spring constant 𝐾 and compresses it by length 𝐿. The maximum momentum of the block after collision is
The block of mass 𝑀 moving on the frictionless horizontal surface collides with the spring of spring constant 𝐾 and compresses it by length 𝐿. The maximum momentum of the block after collision is
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