The angle of projection at which the horizontal range and maximum height of projectile are equal is

Question : The angle of projection at which the horizontal range and maximum height of projectile are equal is

(A) 45°

(B) $\theta =\tan ^{-1}\left( 0.25\right)$

(C) $\theta =\tan ^{-1}\left( 4\right)$

(D) 60°

Answer : option (C)

Solution :

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