**Question** : Let A, B, C, D be independent events such that P(A)=1/2, P(B)=1/3 , P(C)=1/5 and P(D)=1/6 . Then the probability that none of A, B, C and D occurs

(A) 1/180

(B) 1/45

(C) 1/18

(D) none of these

**Answer** : option (B)

**Solution** :

with
no comment

**Question** : Let A, B, C, D be independent events such that P(A)=1/2, P(B)=1/3 , P(C)=1/5 and P(D)=1/6 . Then the probability that none of A, B, C and D occurs

(A) 1/180

(B) 1/45

(C) 1/18

(D) none of these

**Answer** : option (B)

**Solution** :