Question : Let A, B, C, D be independent events such that P(A)=1/2, P(B)=1/3 , P(C)=1/5 and P(D)=1/6 . Then the probability that none of A, B, C and D occurs
(A) 1/180
(B) 1/45
(C) 1/18
(D) none of these
Answer : option (B)
Solution :
Let A, B, C, D be independent events such that P(A)=1/2, P(B)=1/3 , P(C)=1/5 and P(D)=1/6 . Then the probability that none of A, B, C and D occurs
with
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