Question : If the velocity 𝑣 of a particle moving along a straight line decreases linearly with its displacement s from 20ms −1 to a value approaching zero 𝑠 = 30 m, then acceleration of the particle at s = 15m is

(A) \dfrac{2}{3}ms^{-2}
(B) -\dfrac{2}{3}ms^{-2}
(C) \dfrac{20}{3}ms^{-2}
(D) -\dfrac{20}{3}ms^{-2}
Answer : option (D)
Solution :
