Question : From the top of tower, a stone is thrown up. It reaches the ground in 𝑡1 second. A second stone thrown down with the same speed reaches the ground in 𝑡2 second. A third stone released from rest reaches the ground in 𝑡3 second. Then
(A) t_{3}=\dfrac{\left( t_{1}+t_{2}\right) }{2}
(B) t_{3}=\sqrt{t_{1}t_{2}}
(C) \dfrac{1}{t^{3}}=\dfrac{1}{t_{1}}-\dfrac{1}{t_{2}}
(D) t_{3}^{2}=t_{2}^{2}-t_{1}^{2}
Answer : option (B)
Solution :
