From the top of tower, a stone is thrown up. It reaches the ground in 𝑡1 second. A second stone thrown down with the same speed reaches the ground in 𝑡2 second. A third stone released from rest reaches the ground in 𝑡3 second. Then

Question : From the top of tower, a stone is thrown up. It reaches the ground in 𝑡1 second. A second stone thrown down with the same speed reaches the ground in 𝑡2 second. A third stone released from rest reaches the ground in 𝑡3 second. Then

(A) t_{3}=\dfrac{\left( t_{1}+t_{2}\right) }{2}

(B) t_{3}=\sqrt{t_{1}t_{2}}

(C) \dfrac{1}{t^{3}}=\dfrac{1}{t_{1}}-\dfrac{1}{t_{2}}

(D) t_{3}^{2}=t_{2}^{2}-t_{1}^{2}

Answer : option (B)

Solution :

From the top of tower, a stone is thrown up. It reaches the ground in 𝑡1 second. A second stone thrown down with the same speed reaches the ground in 𝑡2 second. A third stone released from rest reaches the ground in 𝑡3 second. Then

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