Question : From the top of a tower, a particle is thrown vertically downwards with a velocity of 10ms−1 . The ratio of the distances covered by it in the 3rd and 2nd seconds of its motion is (Given, g = 10ms −2 )
(A) 7:5
(B) 3:4
(C) 4:3
(D) 6:5
Answer : option (A)
Solution :
