From the top of a tower, a particle is thrown vertically downwards with a velocity of 10ms−1 . The ratio of the distances covered by it in the 3rd and 2nd seconds of its motion is (Given, g = 10ms −2 )

April 15, 2022

by Ezee_Notes

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Physics Problems

Question : From the top of a tower, a particle is thrown vertically downwards with a velocity of 10ms−1 . The ratio of the distances covered by it in the 3rd and 2nd seconds of its motion is (Given, g = 10ms −2 )

(A) 7:5

(B) 3:4

(D) 6:5

Answer : option (A)

Solution :

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10ms−1 . The ratio of the distances covered by it in the 3rd and 2nd seconds of its motion is (Given, g = 10ms −2 )