Question : From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )
(A) 5 ∶ 7
(B) 7 ∶ 5
(C) 3 ∶ 6
(D) 6 ∶ 3
Answer : option (B)
Solution :
