From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )

April 14, 2022

by Ezee_Notes

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Physics Problems

Question : From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )

(A) 5 ∶ 7

(B) 7 ∶ 5

(D) 6 ∶ 3

Answer : option (B)

Solution :

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )