From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )

Question : From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 𝑚 /𝑠𝑒𝑐. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take 𝑔 = 10 𝑚/𝑠 2 )