For a projectile the ratio of maximum height reached to the square of time of flight is (g = 10 ms−1

Question : For a projectile the ratio of maximum height reached to the square of time of flight is (g = 10 ms−1

(A) 5:1

(B) 5:2

(C) 5:4

(D) 1:1

Answer : option (C)

Solution :

For a projectile the ratio of maximum height reached to the square of time of flight is (g = 10 ms−1
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