Question : For a projectile the ratio of maximum height reached to the square of time of flight is (g = 10 ms−1
(A) 5:1
(B) 5:2
(C) 5:4
(D) 1:1
Answer : option (C)
Solution :

Question : For a projectile the ratio of maximum height reached to the square of time of flight is (g = 10 ms−1
(A) 5:1
(B) 5:2
(C) 5:4
(D) 1:1
Answer : option (C)
Solution :