Question: For a particle in uniform circular motion, thee acceleration 𝑎 at a point 𝑃(𝑅, 𝜃) on the circle of radius R is (Here 𝜃 is measured from the x-axis)
(A) \dfrac{v^{2}}{R}\widehat{l}+\dfrac{v^{2}}{R}\widehat{j}
(B) -\dfrac{v^{2}}{R}\cos \theta \widehat{l}+\dfrac{v^{2}}{R}\sin \theta \widehat{j}
(C) -\dfrac{v^{2}}{R}\sin \theta \widehat{l}+\dfrac{v^{2}}{R}\cos \theta \widehat{j}
(D) -\dfrac{v^{2}}{R}\cos \theta \widehat{l}-\dfrac{v^{2}}{R}\sin \theta \widehat{j}
Answer: option (D)
Solution:
