An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dv/dt = 2.5 √v where v is the instantaneous speed. The time taken by the object, to come to rest would be

Question : An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dv/dt=2.5 √v where v is the instantaneous speed. The time taken by the object, to come to rest would be

(a) 1 s

(b) 2 s

(c) 4 s

(d) 8 s

Answer : The Right option is (b)

Solution :

An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dv/dt = 2.5
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