An object moves at a constant speed along a circular path in a horizontal π‘‹π‘Œ plane, with the center at the origin. When the object is at π‘₯ = βˆ’2π‘š, its velocity is βˆ’(4π‘š/𝑠)𝑗̂. What is the object’s acceleration when it is 𝑦 = 2m

Question : An object moves at a constant speed along a circular path in a horizontal π‘‹π‘Œ plane, with the center at the origin. When the object is at π‘₯ = βˆ’2π‘š, its velocity is βˆ’(4π‘š/𝑠)𝑗̂. What is the object’s acceleration when it is 𝑦 = 2m

(A) -\left( 8m/s^{2}\right)𝑗̂

(B) -\left( 8m/s^{2}\right)𝑖̂

(C) -\left( 4m/s^{2}\right)𝑗̂

(D) -\left( 4m/s^{2}\right)𝑖̂

Answer : option (A)

Solution :

An object moves at a constant speed along a circular path in a horizontal π‘‹π‘Œ plane, with the center at the origin. When the object is at π‘₯ = βˆ’2π‘š, its velocity is βˆ’(4π‘š/𝑠)𝑗̂. What is the object’s acceleration when it is 𝑦 = 2m
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