Question : A stone dropped from a building of height ℎ and it reaches after 𝑡 seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity 𝑢 and they reach the earth surface after 𝑡1 and 𝑡2 seconds respectively, then
(A) 𝑡 = 𝑡1 − 𝑡2
(B) t=\dfrac{t_{1}+t_{2}}{2}
(C) t=\sqrt{t_{1}t_{2}}
(D) t=t_{1}^{2}t_{2}^{2}
Answer : option (C)
Solution :
