# A six-faced dice is so biased that it is twice as likely to show an even number as an odd number when thrown. It is thrown twice, the probability that the sum of two numbers thrown is even is

Question : A six-faced dice is so biased that it is twice as likely to show an even number as an odd number when thrown. It is thrown twice, the probability that the sum of two numbers thrown is even is

(A) 1/12

(B) 1/6

(C) 1/3

(D) 5/9

$\dfrac{1}{3}\times \dfrac{1}{3}+\dfrac{2}{3}\times \dfrac{2}{3}=\dfrac{1}{9}+\dfrac{4}{9}=\dfrac{5}{9}$