Question: A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1𝑚/𝑠 so as to have same 𝐾. 𝐸. as that of the boy. The original speed of the man will be
(A) \sqrt{2} 𝑚/𝑠
(B) \left( \sqrt{2}-1\right) 𝑚/𝑠
(C) \dfrac{1}{\left( \sqrt{2}-1\right) } 𝑚/𝑠
(D) \dfrac{1}{\sqrt{2}}
Answer: Option (C)
Solution:
