**Question :** A projectile is thrown at angle β with vertical. It reaches a maximum height 𝐻. The time taken to reach the highest point of its path is

(A) \sqrt{\dfrac{H}{g}}

(B) \sqrt{\dfrac{2H}{g}}

(C) \sqrt{\dfrac{H}{2g}}

(D) \sqrt{\dfrac{2H}{g\cos \beta }}

**Answer :** option (B)

**Solution :**

*Related*