Question : A projectile is thrown at angle β with vertical. It reaches a maximum height 𝐻. The time taken to reach the highest point of its path is
(A) \sqrt{\dfrac{H}{g}}
(B) \sqrt{\dfrac{2H}{g}}
(C) \sqrt{\dfrac{H}{2g}}
(D) \sqrt{\dfrac{2H}{g\cos \beta }}
Answer : option (B)
Solution :
