A plumb line is suspended from a ceiling of a car moving with horizontal acceleration ofπ‘Ž. What will be the angle of inclination with vertical?

Question : A plumb line is suspended from a ceiling of a car moving with horizontal acceleration ofπ‘Ž. What will be the angle of inclination with vertical?

(A) \tan ^{-1}\left( \dfrac{a}{g}\right)

(B) \tan ^{-1}\left( \dfrac{g}{a}\right)

(C) cas ^{-1}\left( \dfrac{a}{g}\right)

(D) cas ^{-1}\left( \dfrac{g}{a}\right)

Answer : option (A)

Solution :

A plumb line is suspended from a ceiling of a car moving with horizontal acceleration ofπ‘Ž. What will be the angle of inclination with vertical?
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