Question: A particle of mass 𝑚 moving with velocity 𝑉0 strikes a simple pendulum of mass 𝑚 and strikes to it. The maximum height attained by the pendulum will be
(A) h=\dfrac{v_{0}^{2}}{8g}
(B) \sqrt{V_{0}g}
(C) 2\sqrt{\dfrac{V_{0}}{g}}
(D) \dfrac{V_{0}^{2}}{4g}
Answer: Option (A)
Solution:
