Question : A particle of mass 𝑚 is projected with a velocity 𝑣 making an angle of 45° with the horizontal. The magnitude of angular momentum of projectile about the point of projection when the particle is at its maximum height ℎ is
(A) zero
(B) \dfrac{mvh}{\sqrt{2}}
(C) \dfrac{mvh^{2}}{\sqrt{2}}
(D) none of these
Answer : option (B)
Solution :
