Question : A particle of mass 𝑚 is projected with a velocity 𝑣 making an angle of 30° with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height ℎ is
(A) \dfrac{3}{2}\dfrac{mv^{2}}{g}
(B) zero
(C) \dfrac{mv^{3}}{2g}
(D) \dfrac{\sqrt{3}}{16}\dfrac{mv^{3}}{g}
Answer : option (D)
Solution :
