Question: A particle moves along the xβπxis from x= π₯1 π‘π π₯ = π₯2 under the action of a force given by F=2π₯. Then the work done in the process is
(A) Zero
(B) x_{2}^{2}-x_{1}^{2}
(C) 2x_{2}\left( x_{2}-x_{1}\right)
(D) 2x_{1}\left( x_{1}-x_{2}\right)
Answer: Option (B)
Solution:
