A particle moves along π‘₯ βˆ’axis in such a way that its coordinate (π‘₯) varies with time 𝑑 according to the
expression π‘₯ = 2 βˆ’ 5𝑑 + 6𝑑
2m, the initial velocity of the particle is

Question : A particle moves along π‘₯ βˆ’axis in such a way that its coordinate (π‘₯) varies with time 𝑑 according to the expression π‘₯ = 2 βˆ’ 5𝑑 + 6𝑑 2m, the initial velocity of the particle is

(A) 3ms^{-1}

(B) 6ms^{-1}

(C) -3ms^{-1}

(D) -5ms^{-1}

Answer : option (D)

Solution :

A particle moves along π‘₯ βˆ’axis in such a way that its coordinate (π‘₯) varies with time 𝑑 according to the
expression π‘₯ = 2 βˆ’ 5𝑑 + 6𝑑
2m, the initial velocity of the particle is
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