A particle is projected with a velocity 𝑣 such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where 𝑔 is acceleration due to gravity)

Question : A particle is projected with a velocity 𝑣 such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where 𝑔 is acceleration due to gravity)

(A) \dfrac{4v^{2}}{5g}

(B) \dfrac{4g}{5v^{2}}

(C) \dfrac{v^{2}}{g}

(D) \dfrac{4v^{2}}{\sqrt{5}g}

Answer : option (A)

Solution :

A particle is projected with a velocity 𝑣 such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where 𝑔 is acceleration due to gravity)
Tags: No tags

Add a Comment

Your email address will not be published. Required fields are marked *