# A particle is projected with a velocity 𝑣 such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where 𝑔 is acceleration due to gravity)

Question : A particle is projected with a velocity 𝑣 such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where 𝑔 is acceleration due to gravity)

(A) $\dfrac{4v^{2}}{5g}$

(B) $\dfrac{4g}{5v^{2}}$

(C) $\dfrac{v^{2}}{g}$

(D) $\dfrac{4v^{2}}{\sqrt{5}g}$

Answer : option (A)

Solution :

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