Question: A particle is projected from the ground with an initial speed of 𝑣 at an angle θ with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is
(A) \dfrac{v}{2}\sqrt{1+2\cos ^{2}\theta }
(B) \dfrac{v}{2}\sqrt{1+\cos ^{2}\theta }
(C) \dfrac{v}{2}\sqrt{1+3\cos ^{2}\theta }
(D) 𝑣 cos θ
Answer: option (C)
Solution:
