A particle is projected from a point 𝐴 with velocity 𝑢√2 at an angle of 45° with horizontal as shown in figure. It strikes the plane 𝐵𝐶 at right angles. The velocity of the particle at the time of collision is

Question : A particle is projected from a point 𝐴 with velocity 𝑢√2 at an angle of 45° with horizontal as shown in figure. It strikes the plane 𝐵𝐶 at right angles. The velocity of the particle at the time of collision is

(A) \dfrac{\sqrt{3}u}{2}

(B) \dfrac{u}{2}

(C) \dfrac{2u}{\sqrt{3}}

(D) u

Answer : option (C)

Solution :

A particle is projected from a point 𝐴 with velocity 𝑢√2 at an angle of 45° with horizontal as shown in figure. It strikes the plane 𝐵𝐶 at right angles. The velocity of the particle at the time of collision is
Tags: No tags

Add a Comment

Your email address will not be published. Required fields are marked *