Question : A particle is projected from a point 𝐴 with velocity 𝑢√2 at an angle of 45° with horizontal as shown in figure. It strikes the plane 𝐵𝐶 at right angles. The velocity of the particle at the time of collision is
(A) \dfrac{\sqrt{3}u}{2}
(B) \dfrac{u}{2}
(C) \dfrac{2u}{\sqrt{3}}
(D) u
Answer : option (C)
Solution :
