Question: A particle is moving in a circle of radius 𝑅 in such a way that at any instant the normal and tangential components of its acceleration are equal. If its speed at 𝑡 = 0 is 𝑣0, the time taken to complete the first revolution is
(A) \dfrac{R}{v_{0}}
(B) \dfrac{R}{v_{0}}\left( 1-e^{-2\pi }\right)
(C) \dfrac{R}{v_{0}}e^{-2\pi }
(D) \dfrac{2\pi R}{v_{0}}
Answer: option (B)
Solution:
