A particle crossing the origin of co-ordinates at time 𝑑 = 0, moves in the π‘₯𝑦 βˆ’plane with a constant acceleration π‘Ž in the 𝑦 βˆ’ direction. If its equation of motion is 𝑦 = 𝑏π‘₯2 (𝑏 is a constant), its velocity component in the π‘₯ βˆ’direction is

Question : A particle crossing the origin of co-ordinates at time 𝑑 = 0, moves in the π‘₯𝑦 βˆ’plane with a constant acceleration π‘Ž in the 𝑦 βˆ’ direction. If its equation of motion is 𝑦 = 𝑏π‘₯2 (𝑏 is a constant), its velocity component in the π‘₯ βˆ’direction is

(A) \sqrt{\dfrac{2b}{a}}

(B) \sqrt{\dfrac{a}{2b}}

(C) \sqrt{\dfrac{a}{b}}

(D) \sqrt{\dfrac{b}{a}}

Answer : option (B)

Solution :

A particle crossing the origin of co-ordinates at time 𝑑 = 0, moves in the π‘₯𝑦 βˆ’plane with a constant acceleration π‘Ž in the 𝑦 βˆ’ direction. If its equation of motion is 𝑦 = 𝑏π‘₯2 (𝑏 is a constant), its velocity component in the π‘₯ βˆ’direction is
Tags: No tags

Add a Comment

Your email address will not be published. Required fields are marked *