A juggler keeps on moving four balls in the air throws the balls in regular interval of time. When one ball leaves his hand (speed=20ms −1 ), the position of other ball will be (Take g = 10ms −2 )

April 10, 2022

by Ezee_Notes

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Physics Problems

Question : A juggler keeps on moving four balls in the air throws the balls in regular interval of time. When one ball leaves his hand (speed=20ms −1 ), the position of other ball will be (Take g = 10ms −2 )

(A) 10m, 20m, 10m

(B) 15m, 20m, 15m

(D) 5m, 10m, 20m

Answer : option (C)

Solution :

A juggler keeps on moving four balls in the air throws the balls in regular interval of time. When one ball leaves his hand (speed=20ms −1 ), the position of other ball will be (Take g = 10ms −2 )