A glass marble projected horizontally from the top of a table falls at a distance π‘₯ from the edge of the table. If β„Ž is the height of the table, then the velocity of projection is

Question: A glass marble projected horizontally from the top of a table falls at a distance π‘₯ from the edge of the table. If β„Ž is the height of the table, then the velocity of projection is

(A) h\sqrt{\dfrac{g}{2x}}

(B) x\sqrt{\dfrac{g}{2x}}

(C) gπ‘₯β„Ž

(D) gπ‘₯ + β„Ž

Answer: option (B)

Solution:

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