A force of (10î− 3ĵ+ 6k̂) N acts on a body of mass 100 g and displaces it from (6î+ 5ĵ− 3k̂) m to (10î−2ĵ+ 7k̂) m. The work done is

Question : A force of (10î− 3ĵ+ 6k̂) N acts on a body of mass 100 g and displaces it from (6î+ 5ĵ− 3k̂) m to (10î−2ĵ+ 7k̂) m. The work done is

(A) 21 J

(B) 121 J

(C) 361 J

(D) 1000 J

Answer : option (B)

Solution :

A force of (10î− 3ĵ+ 6k̂) N acts on a body of mass 100 g and displaces it from (6î+ 5ĵ− 3k̂) m to (10î−2ĵ+ 7k̂) m. The work done is
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