A force F= βˆ’K𝐾(𝑦iΜ‚+ π‘₯j)Μ‚ (where 𝐾 is a positive constant) acts on a particle moving in the π‘₯ βˆ’ Y plane. Starting from the origin, the particle is taken along the positive π‘₯-axis to the point (π‘Ž, 0) and then parallel to the 𝑦-axis to the (π‘Ž,a). The total work done by the force Fβƒ— on the particle is

Question : A force F= βˆ’K𝐾(𝑦iΜ‚+ π‘₯j)Μ‚ (where 𝐾 is a positive constant) acts on a particle moving in the π‘₯βˆ’ Y plane. Starting from the origin, the particle is taken along the positive π‘₯-axis to the point (a, 0) and then parallel to the 𝑦-axis to the (π‘Ž,a). The total work done by the force Fβƒ— on the particle is

(A) -2ka^{2}

(B) 2ka^{2}

(C) -ka^{2}

(D) ka^{2}

Answer : option (D)

Solution :

A force F= βˆ’K𝐾(𝑦iΜ‚+ π‘₯j)Μ‚ (where 𝐾 is a positive constant) acts on a particle moving in the π‘₯ βˆ’ Y plane. Starting from the origin, the particle is taken along the positive π‘₯-axis to the point (π‘Ž, 0) and then parallel to the 𝑦-axis to the (π‘Ž,a). The total work done by the force Fβƒ— on the particle is
Tags: No tags

Add a Comment

Your email address will not be published. Required fields are marked *