Question: A force acts on a 30 𝑔 particle in such a way that the position of the particle as a function of time is given by 𝑥 = 3𝑡 − 4𝑡 2 + 𝑡 3 , where 𝑥 is in 𝑚𝑒𝑡𝑟𝑒𝑠 and 𝑡 is in seconds. The work done during the first 4 seconds is
(A) 5.28 𝐽
(B) 450 𝑚𝐽
(C) 190 𝑚𝐽
(D) 530 𝑚J
Answer: Option (A)
Solution:
