**Question **: A die is rolled 4 times. The probability of getting a larger number than the previous number each time is

(A) 17/216

(B) 5/432

(C) 15/432

(D) none of these

**Answer **: option (B)

**Solution **:

Given that, n(S) = 6 × 6 × 6 × 6 = 6^{4}

The number of favourable ways is 6C_{4}=\dfrac{6\times 5}{2}=15

therefore, the required probability is,

\dfrac{15}{6\times 216}-\dfrac{5}{2\times 216}\Rightarrow \dfrac{5}{432}

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