**Question** : A coin is tossed 2n times. The chance that the number of times one gets head is not equal to the number of times one gets tails is

(A) \dfrac{\left( 2n!\right) }{\left( n!\right) ^{2}}\left( \dfrac{1}{2}\right) ^{2n}

(B) 1-\dfrac{\left( 2n!\right) }{\left( n!\right) ^{2}}

(C) 1-\dfrac{\left( 2n!\right) }{\left( n!\right) ^{2}}\dfrac{1}{4^{n}}

(D) none of these

**Answer** : option (C)

**Solution **:

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