A car, starting from rest, accelerates at the rate 𝑓 through a distance 𝑆, then continues at constant speed for time 𝑑 and then decelerates at the rate 𝑓/2 to come to rest. If the total distance traversed is 15 𝑆, then

Question : A car, starting from rest, accelerates at the rate 𝑓 through a distance 𝑆, then continues at constant speed for time 𝑑 and then decelerates at the rate 𝑓/2 to come to rest. If the total distance traversed is 15 𝑆, then

(A) S=\dfrac{1}{2}ft^{2}

(B) S=\dfrac{1}{4}ft^{2}

(C) S=\dfrac{1}{72}ft^{2}

(D) S=\dfrac{1}{6}ft^{2}

Answer : option (C)

Solution :

A car, starting from rest, accelerates at the rate 𝑓 through a distance 𝑆, then continues at constant speed for time 𝑑 and then decelerates at the rate 𝑓/2 to come to rest. If the total distance traversed is 15 𝑆, then
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