A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 ms−1 at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? (𝑔 = 10 ms−2 , sin 30° = 1/2, cos 30° = √3/2

Question : A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 ms−1 at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? (𝑔 = 10 ms−2 , sin 30° = 1/2, cos 30° = √3/2

(A) 5.20 m

(B) 4.33 m

(C) 2.60 m

(d) 8.66 m

Answer : option (D)

Solution :

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 ms−1 at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? (𝑔 = 10 ms−2 , sin 30° = 1/2, cos 30° = √3/2
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