Question : A bomber plane moves horizontally with a speed of 500 𝑚/𝑠 and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (𝑔 = 10 𝑚/𝑠 2 )
(A) \tan ^{-1}\left( \dfrac{1}{5}\right)
(B) \tan ^{-1}\left( \dfrac{1}{2}\right)
(C) \tan ^{-1}\left( 1\right)
(D) \tan ^{-1}\left( 5\right)
Answer : option (A)
Solution :
