A bomber plane moves horizontally with a speed of 500 𝑚/𝑠 and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (𝑔 = 10 𝑚/𝑠 2 )

Question : A bomber plane moves horizontally with a speed of 500 𝑚/𝑠 and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (𝑔 = 10 𝑚/𝑠 2 )

(A) \tan ^{-1}\left( \dfrac{1}{5}\right)

(B) \tan ^{-1}\left( \dfrac{1}{2}\right)

(C) \tan ^{-1}\left( 1\right)

(D) \tan ^{-1}\left( 5\right)

Answer : option (A)

Solution :

A bomber plane moves horizontally with a speed of 500 𝑚/𝑠 and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be (𝑔 = 10 𝑚/𝑠 2 )
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