**Question **: A body thrown with some velocity reaches the maximum height of 50m. Another body with Double the mass thrown up with double the initial velocity will reach a maximum height of

(a) 100m

(b) 200m

(c) 300m

(d) 400m

**Answer** : Option (b)

**Solution** :

H_{\max }\alpha u^{2}
It body projected with double velocity then maximum height will become four times

\dfrac{H_{1}}{H_{2}}=\left( \dfrac{u_{1}}{u_{2}}\right) ^{2}\Rightarrow \dfrac{50}{H_{2}}=\left( \dfrac{4}{2u}\right) ^{2}\Rightarrow 200m

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