Question : A body thrown with some velocity reaches the maximum height of 50m. Another body with Double the mass thrown up with double the initial velocity will reach a maximum height of
(a) 100m
(b) 200m
(c) 300m
(d) 400m
Answer : Option (b)
Solution :
H_{\max }\alpha u^{2}It body projected with double velocity then maximum height will become four times
\dfrac{H_{1}}{H_{2}}=\left( \dfrac{u_{1}}{u_{2}}\right) ^{2}\Rightarrow \dfrac{50}{H_{2}}=\left( \dfrac{4}{2u}\right) ^{2}\Rightarrow 200m