A body thrown vertically up to reach its maximum height in š‘” second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is

Question : A body thrown vertically up to reach its maximum height in š‘” second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is

(A) \sqrt{2}t

(B) \left( 1+\dfrac{1}{\sqrt{2}}\right) t

(C) \dfrac{3t}{2}

(D) \dfrac{t}{\sqrt{2}}

Answer : option (D)

Solution :

A body thrown vertically up to reach its maximum height in š‘” second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is
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