Question : A body thrown vertically up to reach its maximum height in š” second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is
(A) \sqrt{2}t
(B) \left( 1+\dfrac{1}{\sqrt{2}}\right) t
(C) \dfrac{3t}{2}
(D) \dfrac{t}{\sqrt{2}}
Answer : option (D)
Solution :
