Question : A body projected vertically upwards crosses a point twice in its journey at a height β just after π‘1 and π‘2 second. Maximum height reached by the body is
(A) \dfrac{g}{4}\left( t_{1}+t_{2}\right) ^{2}
(B) \left( \dfrac{t_{1}+t_{2}}{4}\right) ^{2}
(C) 2g\left( \dfrac{t_{1}+t_{2}}{4}\right) ^{2}
(D) \dfrac{9}{4}\left( t_{1}t_{2}\right)
Answer : option (C)
Solution :
