Question: A body of mass 3 kg acted upon by a constant force is displaced by 𝑆 meter, given by relation S =1/3 t 2 , where t is in second. Work done by the force in 2 seconds is
(A) \dfrac{8}{3}
(B) \dfrac{19}{5}
(C) \dfrac{5}{19}
(D) \dfrac{3}{8}
Answer: Option (A)
Solution:
