Question : A body is projected vertically upwards. The times corresponding to height ℎ while ascending and while descending are 𝑡1 and 𝑡2 respectively. Then the velocity of projection is (g is acceleration due to gravity)
(A) g\sqrt{t_{1}t_{2}}
(B) \dfrac{gt_{1}t_{2}}{t_{1}+t_{2}}
(C) \dfrac{g\sqrt{t_{1}t_{2}}}{2}
(D) \dfrac{g\left( t_{1}+t_{2}\right) }{2}
Answer : option (D)
Solution :
