A ball is projected upwards from a height ℎ above the surface of the earth with velocity 𝑣. The time at which the ball strikes the ground is April 13, 2022 by Ezee_Notes with no comment Physics Problems Question : A ball is projected upwards from a height ℎ above the surface of the earth with velocity 𝑣. The time at which the ball strikes the ground is (A) \dfrac{v}{g}+\dfrac{2hg}{\sqrt{2}} (B) \dfrac{v}{g}\left[ 1-\sqrt{1+\dfrac{2h}{g}}\right] (C) \dfrac{v}{g}( 1-\sqrt{1+\dfrac{2gh}{v^{2}}}] (D) \dfrac{v}{g}\left[ 1+\sqrt{v^{2}+\dfrac{2h}{g}}\right] Answer : option (C) Solution : Related Previous Post The wind appears to blow from the north to a man moving in the north-east direction. When he doubles his velocity the wind appears to move in the direction cot−1 (2) east of north. The actual direction of the wind is Next Post A stone dropped from a balloon which is at a height ℎ, reaches the ground after 𝑡 second. From the same balloon, if two stones are thrown, one upwards and the other downwards, with the same velocity 𝑢 and they reach the ground after 𝑡1and 𝑡2 second respectively, then