Question : A ball is projected upwards from a height ℎ above the surface of the earth with velocity 𝑣. The time at which the ball strikes the ground is
(A) \dfrac{v}{g}+\dfrac{2hg}{\sqrt{2}}
(B) \dfrac{v}{g}\left[ 1-\sqrt{1+\dfrac{2h}{g}}\right]
(C) \dfrac{v}{g}( 1-\sqrt{1+\dfrac{2gh}{v^{2}}}]
(D) \dfrac{v}{g}\left[ 1+\sqrt{v^{2}+\dfrac{2h}{g}}\right]
Answer : option (C)
Solution :
